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7n^2-8=132
We move all terms to the left:
7n^2-8-(132)=0
We add all the numbers together, and all the variables
7n^2-140=0
a = 7; b = 0; c = -140;
Δ = b2-4ac
Δ = 02-4·7·(-140)
Δ = 3920
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3920}=\sqrt{784*5}=\sqrt{784}*\sqrt{5}=28\sqrt{5}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-28\sqrt{5}}{2*7}=\frac{0-28\sqrt{5}}{14} =-\frac{28\sqrt{5}}{14} =-2\sqrt{5} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+28\sqrt{5}}{2*7}=\frac{0+28\sqrt{5}}{14} =\frac{28\sqrt{5}}{14} =2\sqrt{5} $
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